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Project Euler Problem One

Leonhard Euler, from their website) Project Euler is a series of challenging mathematical/computer programming problems that will require more than just mathematical insights to solve. Although mathematics will help you arrive at elegant and efficient methods, the use of a computer and programming skills will be required to solve most problems.

I decided to take a crack or two at these, even though a trillion people have done these before me (32,022 registered answers as of the time that I’m writing this). My goal is to try to do this in whatever way occurs to me at first, and then to try to solve the problem using some new technique. Over the course of solving these problems, I want to try to dig a little into F#, Ruby, C# 3.0, or whatever seems like it might be cool 🙂

Today, I attack Problem One. I’ve included the answer in the comments, so don’t read on if you don’t want to know.

Okay, that was a snoozefest. I was reading in the Pro LINQ book (the one that gave me this post) and I found Enumerable.Range. Do the wonders of LINQ never cease? Enumerable.Range will generate a range of numbers for you so that you don’t have to do a loop. Then, you could use that range to then perform a lambda on (the divisible by 3 or 5 check) and then just sum the remaining list. It turns out that this kind of thing is *exactly* what LINQ will just knock out for you. Check the resulting code.

Same answer? Check. Learned and used something new in the process? Check. Looks like I win the nerd prize!

One Comment

Pete on Software  on December 7th, 2008

[…] Last time, I began working on the Project Euler problems and I set out guidelines for myself that I would attempt the problem first in C# (that I’m most comfortable with) and then try to solve the problem in some new way. Last time, I used some of the LINQ extension methods that I hadn’t previously used before. Some solutions might be in F#, Ruby, Python, etc, and I might use each “new way” more than once (since 10 lines of code doesn’t make me an expert!). […]

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